(7x^-4/8y^-2)^-3

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Solution for (7x^-4/8y^-2)^-3 equation: 


D( x )

x = 0

((7*x^-4)/8)*y^-2 = 0

x = 0

x = 0

((7*x^-4)/8)*y^-2 = 0

((7*x^-4)/8)*y^-2 = 0

7/8*x^-4*y^-2 = 0 // : 7/8*y^-2

x^-4 = 0

x naleu017Cy do O

x in (-oo:0) U (0:+oo)

(((7*x^-4)/8)*y^-2)^-3 = 0

512/343*x^12*y^6 = 0 // : 512/343*y^6

x^12 = 0

x = 0

x in { 0} 

x belongs to the empty set

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